久久午夜无码免费_丰满爆乳无码一区二区三区_日本少妇被黑人猛CAO_性xxxxx大片免费视频

ATOS放大器是能把輸入訊號的電壓或功率放大的裝置，由電子管或晶體管、電源變壓器和其他電器元件組成。用在通訊、廣播、雷達、電視、自動控制等各種裝置中。
ATOS放大器工作原理圖

ATOS放(fang)大(da)器的(de)(de)技術參(can)數:CA3080是一種被稱為(wei)(wei)OTA的(de)(de)IC它是一種差動輸(shu)(shu)(shu)(shu)入(ru)/電(dian)(dian)(dian)(dian)(dian)(dian)(dian)(dian)(dian)流(liu)(liu)(liu)輸(shu)(shu)(shu)(shu)出(chu)(chu)型的(de)(de)OP放(fang)大(da)器。互導GM用公式GM=△I0/△E1表示。而(er)GM=19.2*IH，所(suo)以可(ke)(ke)得(de)到與偏(pian)流(liu)(liu)(liu)IA成正(zheng)比(bi)的(de)(de)GM。因為(wei)(wei)是電(dian)(dian)(dian)(dian)(dian)(dian)(dian)(dian)(dian)流(liu)(liu)(liu)輸(shu)(shu)(shu)(shu)出(chu)(chu)，其內(nei)陰(yin)RO非(fei)常(chang)大(da)，R≈7500/IA/10的(de)(de)負(fu)3次(ci)方。根(gen)據(ju)以上關系，可(ke)(ke)用下式計算輸(shu)(shu)(shu)(shu)出(chu)(chu)電(dian)(dian)(dian)(dian)(dian)(dian)(dian)(dian)(dian)流(liu)(liu)(liu)I：I=GM.E1=19.2*IA.EIO 再用A2進行電(dian)(dian)(dian)(dian)(dian)(dian)(dian)(dian)(dian)流(liu)(liu)(liu)電(dian)(dian)(dian)(dian)(dian)(dian)(dian)(dian)(dian)壓(ya)(ya)轉換(huan)(huan)之后可(ke)(ke)獲得(de)輸(shu)(shu)(shu)(shu)出(chu)(chu)電(dian)(dian)(dian)(dian)(dian)(dian)(dian)(dian)(dian)壓(ya)(ya)。根(gen)據(ju)正(zheng)負(fu)EI=IO/19.2*IA，當(dang)IO=1MA，IA=1MA時(shi)(shi)(shi)，CA3080的(de)(de)輸(shu)(shu)(shu)(shu)入(ru)電(dian)(dian)(dian)(dian)(dian)(dian)(dian)(dian)(dian)壓(ya)(ya)正(zheng)負(fu)EI為(wei)(wei)52MV；當(dang)IA=10UA時(shi)(shi)(shi)，則為(wei)(wei)5.2V。IA比(bi)較(jiao)小時(shi)(shi)(shi)，轉換(huan)(huan)速(su)度就會降低，所(suo)以不(bu)能(neng)太小。應(ying)盡量采用較(jiao)大(da)的(de)(de)IA值，并在輸(shu)(shu)(shu)(shu)入(ru)端(duan)R1和R2組(zu)成的(de)(de)電(dian)(dian)(dian)(dian)(dian)(dian)(dian)(dian)(dian)阻(zu)分壓(ya)(ya)電(dian)(dian)(dian)(dian)(dian)(dian)(dian)(dian)(dian)路，調整(zheng)(zheng)(zheng)zui大(da)輸(shu)(shu)(shu)(shu)入(ru)電(dian)(dian)(dian)(dian)(dian)(dian)(dian)(dian)(dian)平，R1的(de)(de)值根(gen)據(ju)用途確定。如果(guo)輸(shu)(shu)(shu)(shu)出(chu)(chu)電(dian)(dian)(dian)(dian)(dian)(dian)(dian)(dian)(dian)流(liu)(liu)(liu)IO按1MA設計，當(dang)zui大(da)輸(shu)(shu)(shu)(shu)出(chu)(chu)為(wei)(wei)正(zheng)負(fu)10V時(shi)(shi)(shi)，OP放(fang)大(da)器A：的(de)(de)反饋電(dian)(dian)(dian)(dian)(dian)(dian)(dian)(dian)(dian)阻(zu)則應(ying)取10/10的(de)(de)負(fu)3次(ci)方千歐(ou)，R5=8.2千歐(ou)，VR2為(wei)(wei)5千歐(ou)（可(ke)(ke)調節）。偏(pian)流(liu)(liu)(liu)IA的(de)(de)輸(shu)(shu)(shu)(shu)入(ru)辦法：為(wei)(wei)了能(neng)使與控制電(dian)(dian)(dian)(dian)(dian)(dian)(dian)(dian)(dian)壓(ya)(ya)VC成正(zheng)比(bi)的(de)(de)電(dian)(dian)(dian)(dian)(dian)(dian)(dian)(dian)(dian)流(liu)(liu)(liu)流(liu)(liu)(liu)過，可(ke)(ke)使用基極(ji)接地的(de)(de)PNP晶體(ti)管(guan)。如基極(ji)電(dian)(dian)(dian)(dian)(dian)(dian)(dian)(dian)(dian)流(liu)(liu)(liu)忽略不(bu)計，輸(shu)(shu)(shu)(shu)入(ru)電(dian)(dian)(dian)(dian)(dian)(dian)(dian)(dian)(dian)流(liu)(liu)(liu)I1N=（VC-VBE）/R4，當(dang)電(dian)(dian)(dian)(dian)(dian)(dian)(dian)(dian)(dian)壓(ya)(ya)VC低于(yu)VBE≈0.5V時(shi)(shi)(shi)，IA則幾乎(hu)等于(yu)0，沒有(you)(you)放(fang)大(da)功能(neng)。由(you)于(yu)整(zheng)(zheng)(zheng)個電(dian)(dian)(dian)(dian)(dian)(dian)(dian)(dian)(dian)路采用直流(liu)(liu)(liu)耦合(he)，所(suo)以OP放(fang)大(da)器A2中加了失(shi)(shi)調調整(zheng)(zheng)(zheng)電(dian)(dian)(dian)(dian)(dian)(dian)(dian)(dian)(dian)路。如果(guo)輸(shu)(shu)(shu)(shu)入(ru)、輸(shu)(shu)(shu)(shu)出(chu)(chu)加了隔直流(liu)(liu)(liu)電(dian)(dian)(dian)(dian)(dian)(dian)(dian)(dian)(dian)容，并且只(zhi)有(you)(you)AC電(dian)(dian)(dian)(dian)(dian)(dian)(dian)(dian)(dian)流(liu)(liu)(liu)渡過時(shi)(shi)(shi)，可(ke)(ke)不(bu)加失(shi)(shi)調調整(zheng)(zheng)(zheng)電(dian)(dian)(dian)(dian)(dian)(dian)(dian)(dian)(dian)路。在A1的(de)(de)反相輸(shu)(shu)(shu)(shu)入(ru)端(duan)，經(jing)過串聯電(dian)(dian)(dian)(dian)(dian)(dian)(dian)(dian)(dian)阻(zu)R7之后進行失(shi)(shi)調調整(zheng)(zheng)(zheng)也可(ke)(ke)以。

ATOS放大器原理(li)：鎖(suo)相放(fang)大器(qi)(qi)(qi)實際上是一個模擬的(de)傅立(li)葉變換器(qi)(qi)(qi)，鎖(suo)相放(fang)大器(qi)(qi)(qi)的(de)輸(shu)出(chu)(chu)是一個直流電壓(ya)，正比于是輸(shu)入(ru)(ru)信(xin)號中(zhong)某一特定頻率(lv)（參數(shu)輸(shu)入(ru)(ru)頻率(lv)）的(de)信(xin)號幅值。而(er)輸(shu)入(ru)(ru)信(xin)號中(zhong)的(de)其他頻率(lv)成分將不(bu)能(neng)對(dui)輸(shu)出(chu)(chu)電壓(ya)構成任何(he)貢獻。
兩個正(zheng)弦(xian)信號，頻率(lv)都為1Hz，有90度(du)相位差，用乘法器相乘得到的(de)結果是一個有直流偏(pian)量的(de)正(zheng)弦(xian)信號。
如果是(shi)一個(ge)1Hz和一個(ge)1.1Hz的(de)信(xin)號(hao)相(xiang)乘，用乘法器相(xiang)乘得到的(de)結果是(shi)輪廓(kuo)為(wei)正弦(xian)的(de)調制信(xin)號(hao)，直流偏量(liang)為(wei)0。
只有(you)(you)與參考信號(hao)頻(pin)率(lv)**的信號(hao)才能在(zai)乘法器(qi)輸出端(duan)得到直流(liu)偏量(liang)，其他信號(hao)在(zai)輸出端(duan)都是交(jiao)流(liu)信號(hao)。如(ru)果(guo)在(zai)乘法器(qi)的輸出端(duan)加一個低通濾波器(qi)，那么(me)所有(you)(you)的交(jiao)流(liu)信號(hao)分(fen)(fen)量(liang)全部被濾掉，剩(sheng)下(xia)的直流(liu)分(fen)(fen)量(liang)就只是正比(bi)于(yu)輸入信號(hao)中的特定(ding)頻(pin)率(lv)的信號(hao)分(fen)(fen)量(liang)的幅值。

E-ME-L-01H 40 /DL17SA
E-ME-L-01H 40 /DL26SB
E-ME-L-01H 40 /DL27SB 
E-ME-L-01H 40 /DL27SB 
E-ME-L-01H 40 /DL27SB 
E-ME-L-01H 40 /DL35SB 
E-ME-L-01H 40 /DL67SA 
E-ME-L-01H 40 /LQ22SA
E-ME-L-01H 40 /LQ32SA
E-ME-L-01H 40/DL27SB
E-ME-L-01H 40/PCNNSA
E-ME-L-01H/DL27SB 
E-ME-L-01H/I 40 /LQ32SA
E-ME-T-01H 40 /DH04SA 
E-ME-T-01H 40 /DH05SA 
E-ME-T-01H 40 /DK14SC 
E-ME-T-01H 40 /DK15SB
E-ME-T-01H 40 /QV0NSA 
E-ME-T-01H 40 /TK14AA 
E-ME-T-01H 40 /TK14SC
E-ME-T-01H 40 /TQ25SA 
E-ME-T-01H 40 /TQ32SA
E-ME-T-01H 40 /TQ42SA